IIT-JEE 2009 · Paper 1 · Chemistry Q2

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ChemistrySingle correct+3 / -1Question 2 of 60

The term that corrects for the attractive forces present in a real gas in the van der Waals equation is

nb

\dfrac{an^2}{V^2}

-\dfrac{an^2}{V^2}

-nb

Answer and worked solution

Official answer: B

van der Waals equation. $\left(P+\dfrac{an^2}{V^2}\right)(V-nb)=nRT$ . Attractions lower the pressure the gas exerts, so the term $\dfrac{an^2}{V^2}$ is added to the measured pressure; $nb$ corrects for the molecules' own volume.

(B)

Topics:Real gases and van der Waals equation

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IIT-JEE 2009 · Paper 1, Chemistry question 2