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← IIT-JEE 2007 · Paper 2
PhysicsMatrix match+6Question 20 of 66

IIT-JEE 2007 · Paper 2, Physics question 20

Column I describes some situations in which a small object moves. Column II describes some characteristics of these motions. Match the situations in Column I with the characteristics in Column II and indicate your answer by darkening appropriate bubbles in the 4 × 4 matrix given in the ORS.

Column I

  • A
    The object moves on the xx-axis under a conservative force in such a way that its "speed" and "position" satisfy v=c1c2−x2v=c_1\sqrt{c_2-x^2}, where c1c_1 and c2c_2 are positive constants.
  • B
    The object moves on the xx-axis in such a way that its velocity and its displacement from the origin satisfy v=−kxv=-kx, where kk is a positive constant.
  • C
    The object is attached to one end of a mass-less spring of a given spring constant. The other end of the spring is attached to the ceiling of an elevator. Initially everything is at rest. The elevator starts going upwards with a constant acceleration aa. The motion of the object is observed from the elevator during the period it maintains this acceleration.
  • D
    The object is projected from the earth's surface vertically upwards with a speed 2GMe/Re2\sqrt{GM_e/R_e}, where, MeM_e is the mass of the earth and ReR_e is the radius of the earth. Neglect forces from objects other than the earth.

Column II

  • P
    The object executes a simple harmonic motion.
  • Q
    The object does not change its direction.
  • R
    The kinetic energy of the object keeps on decreasing.
  • S
    The object can change its direction only once.
Mark every match for each entry
PQRS
A
B
C
D
Answer and worked solution

Official answer: A → P; B → Q, R; C → P; D → Q, R

  • A: v2=c12(c2−x2)v^2=c_1^2(c_2-x^2); differentiating, a=vdvdx=−c12xa=v\frac{dv}{dx}=-c_1^2x: SHM. → P.
  • B: v=−kxv=-kx gives x=x0e−ktx=x_0e^{-kt}: the object approaches the origin without ever turning back, and its speed k∣x∣k|x| keeps decreasing. → Q, R.
  • C: In the elevator frame a pseudo-force mama acts downward. The equilibrium position shifts down by mak\frac{ma}k, and the object, released from the old position, oscillates about the new one: SHM. → P.
  • D: The speed 2GMe/Re2\sqrt{GM_e/R_e} exceeds the escape speed 2GMe/Re\sqrt{2GM_e/R_e}, so the object never comes back: it keeps moving outward while slowing down. → Q, R.

The official key also accepts D → R alone.

Answer: A → P; B → Q, R; C → P; D → Q, R