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← IIT-JEE 2007 · Paper 1
PhysicsMatrix match+6Question 20 of 66

IIT-JEE 2007 · Paper 1, Physics question 20

Some physical quantities are given in Column I and some possible SI units in which these quantities may be expressed are given in Column II. Match the physical quantities in Column I with the units in Column II and indicate your answer by darkening appropriate bubbles in the 4 × 4 matrix given in the ORS.

Column I

  • A
    GMeMsGM_eM_s (GG - universal gravitational constant, MeM_e - mass of the earth, MsM_s - mass of the Sun)
  • B
    3RTM\dfrac{3RT}{M} (RR - universal gas constant, TT - absolute temperature, MM - molar mass)
  • C
    F2q2B2\dfrac{F^2}{q^2B^2} (FF - force, qq - charge, BB - magnetic field)
  • D
    GMeRe\dfrac{GM_e}{R_e} (GG - universal gravitational constant, MeM_e - mass of the earth, ReR_e - radius of the earth)

Column II

  • P
    (volt) (coulomb) (metre)
  • Q
    (kilogram) (metre)³ (second)⁻²
  • R
    (metre)² (second)⁻²
  • S
    (farad) (volt)² (kg)⁻¹
Mark every match for each entry
PQRS
A
B
C
D
Answer and worked solution

Official answer: A → P, Q; B → R, S; C → R, S; D → R, S

  • A, GMeMsGM_eM_s: GMmr2G\frac{Mm}{r^2} is a force, so GMmGMm has units N m² = kg m³ s⁻². Also (volt)(coulomb)(metre) = J m = N m². → P, Q.
  • B, 3RTM\frac{3RT}M: the square of the rms speed, m² s⁻². Also CV2kg\frac{CV^2}{\text{kg}} = J/kg = m² s⁻². → R, S.
  • C, F2q2B2\frac{F^2}{q^2B^2}: F=qvBF=qvB, so this is v2v^2: m² s⁻². → R, S.
  • D, GMeRe\frac{GM_e}{R_e}: =gRe=gR_e, also a squared speed. → R, S.

Answer: A → P, Q; B → R, S; C → R, S; D → R, S