JEE Main 2026 · 8 Apr · Shift 2 · Physics Q50

← JEE Main 2026 · 8 Apr · Shift 2

PhysicsInteger+4 / -1Question 50 of 75

Two masses of 3.4 kg and 2.5 kg are accelerated from an initial speed of 5 m/s and 12 m/s, respectively. The distances traversed by the masses in the 5th second are 104 m and 129 m, respectively. The ratio of their momenta after 10 s is $\dfrac x8$ . The value of $x$ is ________.

Your answer

Answer and worked solution

Official answer: 9

Accelerations. The distance in the nth second is $u+a\left(n-\tfrac12\right)$ :

$5+4.5a_1=104$ , so $a_1=22$ .
$12+4.5a_2=129$ , so $a_2=26$ .

After 10 s. $v_1=225$ and $v_2=272$ :
$\frac{p_1}{p_2}=\frac{3.4\times225}{2.5\times272}=\frac{765}{680}=\frac98.$

Answer: 9

Topics:Motion in a straight line Conservation of linear momentum

← Previous question Next question →

JEE Main 2026 · 8 Apr · Shift 2, Physics question 50