JEE Main 2026 · 8 Apr · Shift 2 · Physics Q41

← JEE Main 2026 · 8 Apr · Shift 2

PhysicsSingle correct+4 / -1Question 41 of 75

Two point charges $q_1=3\ \mu$ C and $q_2=-4\ \mu$ C are placed at points $\left(2\hat i+3\hat j+3\hat k\right)$ and $\left(\hat i+\hat j+\hat k\right)$ respectively. Force on charge $q_2$ is ________ N. $\left(\text{Take }\dfrac1{4\pi\epsilon_0}=9\times10^9\text{ SI Units}\right)$

\left(12\hat i+24\hat j+24\hat k\right)\times10^{-3}

\left(4\hat i+8\hat j+8\hat k\right)\times10^{-3}

\left(3\hat i+6\hat j+6\hat k\right)\times10^{-3}

\left(-4\hat i-8\hat j-8\hat k\right)\times10^{-3}

Answer and worked solution

Official answer: B

Force on $q_2$ . $\vec r=\vec r_2-\vec r_1=(-1,-2,-2)$ , with $|\vec r|=3$ :
$\vec F=\frac{kq_1q_2}{r^3}\vec r=\frac{9\times10^9\times3\times10^{-6}\times(-4\times10^{-6})}{27}(-1,-2,-2)=(4,8,8)\times10^{-3}\text{ N}.$

(Attraction pulls $q_2$ towards $q_1$ .)

(B)

Topics:Coulomb's law and superposition

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JEE Main 2026 · 8 Apr · Shift 2, Physics question 41