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JEE Main 2026 · 8 Apr · Shift 2, Physics question 36

Initial pressure and volume of a monoatomic ideal gas are PP and VV. The change in internal energy of this gas in adiabatic expansion to volume Vfinal=27VV_{final}=27V is ________ J.

Choose one option
Answer and worked solution

Official answer: C

Adiabatic (γ=53\gamma=\tfrac53). TV2/3TV^{2/3} is constant, so Tf=T⋅27−2/3=T9T_f=T\cdot27^{-2/3}=\tfrac T9.

Change.
ΔU=32nR(T9−T)=−43PV.\Delta U=\tfrac32nR\left(\tfrac T9-T\right)=-\tfrac43PV.

(C)

Topics:Thermodynamic processes
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