JEE Main 2026 · 8 Apr · Shift 2 · Physics Q29

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PhysicsSingle correct+4 / -1Question 29 of 75

A gas balloon is going up with a constant velocity of 10 m/s. When this balloon reached a height of 75 m, a stone is dropped from it and balloon keeps moving up with the same velocity. The height of the balloon when the stone hits the ground is ________ m. (Take $g=10$ m/s²)

150

129

125

Answer and worked solution

Official answer: D

Stone. It leaves with 10 m/s upward from 75 m:
$-75=10t-5t^2\ \Rightarrow\ t^2-2t-15=0\ \Rightarrow\ t=5\text{ s}.$

Balloon after 5 s more: $75+50=125$ m.

(D)

Topics:Motion in a straight line

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JEE Main 2026 · 8 Apr · Shift 2, Physics question 29