JEE Main 2026 · 8 Apr · Shift 2 · Physics Q27

PhysicsSingle correct+4 / -1Question 27 of 75

Consider the equation $H=\dfrac{x^p\epsilon^qE^r}{t^s}$

Where $H$ = magnetic field; $E$ = electric field, $\epsilon$ = permittivity, $x$ = distance, $t$ = time

The values of $p$ , $q$ , $r$ and $s$ respectively are :

1, 1, 1, 1

−1, 1, 2, 1

1, −1, −2, 1

−1, −2, −2, 1

Answer and worked solution

Official answer: A

Ampère-Maxwell. $\oint H\,dl=\epsilon\dfrac{d\Phi_E}{dt}$ , so $H\cdot x\sim\epsilon\dfrac{E\,x^2}t$ and $H\sim\dfrac{x\,\epsilon\,E}t$ .

So $p=q=r=s=1$ .

(A)

Topics:Dimensional analysis

JEE Main 2026 · 8 Apr · Shift 2, Physics question 27