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← JEE Main 2026 · 8 Apr · Shift 2
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JEE Main 2026 · 8 Apr · Shift 2, Mathematics question 10

If a straight line drawn through the point of intersection of the lines 4x+3y−1=04x+3y-1=0 and 3x+4y−1=03x+4y-1=0, meets the co-ordinate axes at the points P and Q, then the locus of the mid point of PQ is :

Choose one option
Answer and worked solution

Official answer: B

Intersection. 4x+3y=14x+3y=1 and 3x+4y=13x+4y=1 meet at (17,17)\left(\tfrac17,\tfrac17\right).

Line through it. With midpoint (h,k)(h,k), the intercepts are 2h2h and 2k2k:
1/72h+1/72k=1 ⇒ h+k=14hk.\frac{1/7}{2h}+\frac{1/7}{2k}=1\ \Rightarrow\ h+k=14hk.

Locus: x+y−14xy=0x+y-14xy=0.

(B)