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← JEE Main 2026 · 8 Apr · Shift 2
ChemistrySingle correct+4 / -1Question 68 of 75

JEE Main 2026 · 8 Apr · Shift 2, Chemistry question 68

Which statements are True ?

A. In Hoffmann bromamide degradation, 4 moles of NaOH and 2 moles of BrX2\ce{Br2} are consumed per mole of an amide

B. Hoffmann bromamide reaction is not given by alkyl amides.

C. Primary amines can be synthesized by Hoffmann bromamide degradation.

D. Secondary amide on reaction with BrX2\ce{Br2} and NaOH will give secondary amine.

E. The by-products of Hoffmann degradation are NaX2COX3\ce{Na2CO3}, NaBr and HX2O\ce{H2O}.

Choose the correct answer from the options given below :

Choose one option
Answer and worked solution

Official answer: C

Each statement.

  • A: The reaction RCONHX2+BrX2+4 NaOH→RNHX2+NaX2COX3+2 NaBr+2 HX2O\ce{RCONH2 + Br2 + 4NaOH -> RNH2 + Na2CO3 + 2NaBr + 2H2O} uses 4 NaOH but only 1 BrX2\ce{Br2}. False.
  • B: Alkyl amides do undergo the reaction. False.
  • C: It gives primary amines. True.
  • D: Secondary amides do not give amines this way. False.
  • E: The by-products are NaX2COX3\ce{Na2CO3}, NaBr and HX2O\ce{H2O}. True.

Answer: C and E.

(C)

Topics:Amines