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← JEE Main 2026 · 8 Apr · Shift 2
ChemistrySingle correct+4 / -1Question 60 of 75

JEE Main 2026 · 8 Apr · Shift 2, Chemistry question 60

Given below are two statements :

Statement I : The number of pairs among [TiX4+, VX2+][\ce{Ti^4+},\ \ce{V^2+}], [VX2+, MnX2+][\ce{V^2+},\ \ce{Mn^2+}], [MnX2+, FeX3+][\ce{Mn^2+},\ \ce{Fe^3+}] and [VX2+, CrX2+][\ce{V^2+},\ \ce{Cr^2+}] in which both ions are coloured is 3.

Statement II : The number of pairs among [LaX3+, YbX2+][\ce{La^3+},\ \ce{Yb^2+}], [LuX3+, CeX4+][\ce{Lu^3+},\ \ce{Ce^4+}] and [AcX3+, LrX3+][\ce{Ac^3+},\ \ce{Lr^3+}] ions in which both are diamagnetic is 3.

In the light of the above statements, choose the correct from the options given below :

Choose one option
Answer and worked solution

Official answer: A

Statement I. TiX4+\ce{Ti^4+} (d0d^0) is colourless, so the first pair fails. VX2+\ce{V^2+} (d3d^3), MnX2+\ce{Mn^2+} (d5d^5), FeX3+\ce{Fe^3+} (d5d^5) and CrX2+\ce{Cr^2+} (d4d^4) are all coloured, so the other 3 pairs qualify. Correct.

Statement II. All six ions have empty or full f shells: LaX3+\ce{La^3+} (4f04f^0), YbX2+\ce{Yb^2+} (4f144f^{14}), LuX3+\ce{Lu^3+} (4f144f^{14}), CeX4+\ce{Ce^4+} (4f04f^0), AcX3+\ce{Ac^3+} (5f05f^0), LrX3+\ce{Lr^3+} (5f145f^{14}). All diamagnetic: 3 pairs. Correct.

(A)