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JEE Main 2026 · 8 Apr · Shift 2, Chemistry question 58

Match List - I with List - II.

Choose the correct answer from the options given below :

List - I: Electronic configuration of neutral atom (where n = 2)

  • A
    ns2ns^2
  • B
    ns2np1ns^2np^1
  • C
    ns2np3ns^2np^3
  • D
    ns2np6ns^2np^6

List - II: 1st Ionization Energy (kJ mol⁻¹)

  • I
    2080
  • II
    899
  • III
    800
  • IV
    1402
Choose one option
Answer and worked solution

Official answer: A

Period 2 first ionisation energies.

  • 2s22s^2 (Be): 899 (II).
  • 2s22p12s^22p^1 (B): 800 (III).
  • 2s22p32s^22p^3 (N): 1402 (IV).
  • 2s22p62s^22p^6 (Ne): 2080 (I).

Match: A-II, B-III, C-IV, D-I.

(A)

Topics:Ionisation enthalpy
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