JEE Main 2026 · 8 Apr · Shift 2 · Chemistry Q52

ChemistrySingle correct+4 / -1Question 52 of 75

Given below are two statements :

Given : Molar mass of C, H, O, Cl are 12, 1, 16 and 35.5 g mol $^{-1}$ , respectively

Statement I : In 30% (w/w) solution of methanol in $\ce{CCl4}$ (at T K), the mole fraction of $\ce{CCl4}$ is equal to 0.33.

Statement II : Mixture of methanol and $\ce{CCl4}$ shows positive deviation from Raoult's law.

In the light of the above statements, choose the correct answer from the options given below :

Both Statement I and Statement II are true

Both Statement I and Statement II are false

Statement I is true but Statement II is false

Statement I is false but Statement II is true

Answer and worked solution

Official answer: A

Statement I. 30 g methanol (0.9375 mol) and 70 g $\ce{CCl4}$ (0.4545 mol):
$x_{\ce{CCl4}}=\frac{0.4545}{1.392}\approx0.33.$
True.

Statement II. $\ce{CCl4}$ breaks up methanol's hydrogen bonding, so the mixture shows positive deviation. True.

(A)

Topics:Ideal and non-ideal solutions Concentration terms

JEE Main 2026 · 8 Apr · Shift 2, Chemistry question 52