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← JEE Main 2026 · 6 Apr · Shift 2
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JEE Main 2026 · 6 Apr · Shift 2, Physics question 46

A block takes tt time to slide down a plane inclined at 45° to the horizontal. If the surface is made smooth (frictionless), the block takes time t2\dfrac t2 to slide down the plane. The coefficient of friction between the block and the inclined plane is (α100)\left(\dfrac\alpha{100}\right). The value of α\alpha is ________.

Answer and worked solution

Official answer: 75

Times. t∝1at\propto\dfrac1{\sqrt a}, so taking twice as long means a quarter of the acceleration.

Acceleration with friction.
g(sin⁡45∘−μcos⁡45∘)=14gsin⁡45∘ ⇒ μ=34.g(\sin45^\circ-\mu\cos45^\circ)=\tfrac14g\sin45^\circ\ \Rightarrow\ \mu=\tfrac34.

Answer: α=75\alpha=75