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← JEE Main 2026 · 6 Apr · Shift 2
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JEE Main 2026 · 6 Apr · Shift 2, Physics question 41

The energy released if hydrogen atoms are combined to form 24He^4_2\mathrm{He} is ________ MeV.

(Take binding energies per nucleon of 12H^2_1\mathrm H and 24He^4_2\mathrm{He} as 1.1 MeV and 7.2 MeV, respectively)

Choose one option
Answer and worked solution

Official answer: B

Fusion of two deuterons.
E=4(7.2)−2⋅2(1.1)=28.8−4.4=24.4 MeV.E=4(7.2)-2\cdot2(1.1)=28.8-4.4=24.4\text{ MeV}.

(B)