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← JEE Main 2026 · 6 Apr · Shift 2
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JEE Main 2026 · 6 Apr · Shift 2, Physics question 37

The electric potential as a function of xx, yy is given by V=5(x2−y2)V=5(x^2-y^2) V. The electric field at a point (2,3)(2,3) m is ________ V/m.

Choose one option
Answer and worked solution

Official answer: A

Field. E⃗=−∇V=(−10x, 10y)\vec E=-\nabla V=(-10x,\ 10y). At (2,3)(2,3): −20i^+30j^-20\hat i+30\hat j V/m.

(A)