JEE Main 2026 · 6 Apr · Shift 2 · Physics Q33

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PhysicsSingle correct+4 / -1Question 33 of 75

Figure represents the extension ( $\Delta l$ ) of a wire of length 1 meter, suspended from the ceiling of the room at one end with a load $W$ connected to the other end. If the cross-sectional area of the wire is $10^{-5}$ m² then the Young's modulus of the wire is ________ N/m².

Δl (×10⁻⁴ m) against W (N): a straight line through the origin, with Δl = 1, 2, 3, 4, 5, 6 at W = 10, 20, 30, 40, 50, 60 marked by dashed lines.

1.0\times10^{11}

2.0\times10^{10}

1.0\times10^{10}

2.0\times10^{11}

Answer and worked solution

Official answer: C

Slope. $\dfrac{\Delta l}W=\dfrac{10^{-4}}{10}=10^{-5}$ m/N.

Young's modulus.
$Y=\frac{WL}{A\,\Delta l}=\frac{1}{10^{-5}\times10^{-5}}=1.0\times10^{10}\text{ N/m}^2.$

(C)

Topics:Hooke's law and elastic moduli

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JEE Main 2026 · 6 Apr · Shift 2, Physics question 33