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JEE Main 2026 · 6 Apr · Shift 2, Mathematics question 19

The area of the region {(x,y):x2−8x≤y≤−x}\{(x,y):x^2-8x\le y\le-x\} is :

Choose one option
Answer and worked solution

Official answer: A

Limits. x2−8x≤−xx^2-8x\le-x gives 0≤x≤70\le x\le7.

Area.
∫07(7x−x2) dx=3432−3433=3436.\int_0^7(7x-x^2)\,dx=\frac{343}2-\frac{343}3=\frac{343}6.

(A)

Topics:Area between curves
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