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← JEE Main 2026 · 6 Apr · Shift 2
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JEE Main 2026 · 6 Apr · Shift 2, Mathematics question 1

Let f:R→Rf:\mathbf R\to\mathbf R be defined as f(x)=2x2−3x+23x2+x+3f(x)=\dfrac{2x^2-3x+2}{3x^2+x+3}. Then ff is :

Choose one option
Answer and worked solution

Official answer: D

Not one-one. Replacing x by 1x\tfrac1x:
f(1x)=2−3x+2x23+x+3x2=f(x),f\left(\tfrac1x\right)=\frac{2-3x+2x^2}{3+x+3x^2}=f(x),
so for example f(2)=f(12)f(2)=f\left(\tfrac12\right).

Not onto. The denominator is always positive and f is a bounded rational function (it tends to 23\tfrac23), so it cannot take every real value.

(D)