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← JEE Main 2026 · 6 Apr · Shift 2
ChemistrySingle correct+4 / -1Question 62 of 75

JEE Main 2026 · 6 Apr · Shift 2, Chemistry question 62

Given below are two statements :

Statement I : A mixture of CX12HX22OX11\ce{C12H22O11} (sugar) and NaCl can be separated by dissolving sugar in alcohol, due to differential solubility.

Statement II : Rose essence from rose petals is seperated by steam distillation due to its high volatility and insolubility in HX2O\ce{H2O}.

In the light of the above statements, choose the correct answer from the options given below :

Choose one option
Answer and worked solution

Official answer: A

Statement I. Sugar dissolves in alcohol while NaCl does not, so the mixture is separated by differential solubility. True (as keyed).

Statement II. Rose oil is volatile in steam and immiscible with water, so it is separated by steam distillation. True.

(A)