JEE Main 2026 · 6 Apr · Shift 1 · Physics Q44

← JEE Main 2026 · 6 Apr · Shift 1

PhysicsSingle correct+4 / -1Question 44 of 75

The ratio of momentum of the photons of the 1st and 2nd line of Balmer series of Hydrogen atoms is $\alpha/\beta$ . The possible values of $\alpha$ and $\beta$ are:-

27 and 20

3 and 16

5 and 36

20 and 27

Answer and worked solution

Official answer: D

Balmer lines. Photon momentum is $p=\dfrac h\lambda\propto\dfrac1\lambda$ .

First line: $\tfrac14-\tfrac19=\tfrac5{36}$ .
Second line: $\tfrac14-\tfrac1{16}=\tfrac3{16}$ .

Ratio.
$\frac{5/36}{3/16}=\frac{20}{27}.$

(D)

Topics:Bohr model and hydrogen spectrum Photon momentum and radiation pressure

← Previous question Next question →

JEE Main 2026 · 6 Apr · Shift 1, Physics question 44