JEE Main 2026 · 6 Apr · Shift 1 · Physics Q35

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PhysicsSingle correct+4 / -1Question 35 of 75

Two closed vessels of same volume are joined through a narrow tube and both vessels are filled with air of pressure 90 kPa and temperature 400 K. Keeping the temperature of one vessel constant at 400 K the second vessel temperature is raised to 500 K. The final pressure in the vessels is ________ kPa.

100

120

105

Answer and worked solution

Official answer: A

Total moles are fixed. With the volume V the same for both vessels:
$\frac{2(90)V}{400R}=\frac{PV}R\left(\frac1{400}+\frac1{500}\right).$

Solve. $0.45=P\cdot\dfrac9{2000}$ , so $P=100$ kPa.

(A)

Topics:Ideal gas equation

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JEE Main 2026 · 6 Apr · Shift 1, Physics question 35