JEE Main 2026 · 6 Apr · Shift 1 · Chemistry Q72

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ChemistryInteger+4 / -1Question 72 of 75

Consider the following sequence of reactions.

The percentage of nitrogen in the yellow product (X) formed is ________%. (Nearest Integer)

(Given Molar mass in g mol $^{-1}$ H:1, C:12, N:14)

Diazoaminobenzene, C₆H₅-N=N-NH-C₆H₅, treated with (i) HCl, (ii) aniline (in excess), (iii) warm 40-45 °C, (iv) cool, acetic acid gives a yellow product (X).

Your answer

Answer and worked solution

Official answer: 21

Rearrangement. Diazoaminobenzene, warmed with aniline and a little acid, rearranges to p-aminoazobenzene, $\ce{C6H5N=NC6H4NH2}$ (yellow). Its formula is $\ce{C12H11N3}$ , M = 197.

Nitrogen content.
$\frac{42}{197}\times100=21.3\%.$

Answer: 21

Topics:Diazonium salts Empirical and molecular formula

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JEE Main 2026 · 6 Apr · Shift 1, Chemistry question 72