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← JEE Main 2026 · 6 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 66 of 75

JEE Main 2026 · 6 Apr · Shift 1, Chemistry question 66

Given below are two statements:

Statement I: 3-phenylpropene reacts with HBr and gives secondary alkyl bromide having a chiral carbon atom as the major product.

Statement II: Aryl chlorides and aryl cyanides can be prepared by Sandmeyer reaction as well as Gattermann reaction.

In the light of the above statements, choose the correct answer from the options given below

Choose one option
Answer and worked solution

Official answer: C

Statement I. PhCHX2CH=CHX2\ce{PhCH2CH=CH2} + HBr (Markovnikov) gives PhCHX2CHBrCHX3\ce{PhCH2CHBrCH3}. That is a secondary bromide with a chiral C-2. True.

Statement II. Aryl chlorides form by both Sandmeyer (CuCl\ce{CuCl}) and Gattermann (Cu/HCl). Aryl cyanides form by Sandmeyer (CuCN\ce{CuCN}) only, not by the Gattermann reaction. False.

(C)