JEE Main 2026 · 6 Apr · Shift 1, Chemistry question 52

Lyman series. The shortest line is $n=\infty\to1$: $\dfrac1x=R$.

Balmer series of $\ce{He+}$ ($Z=2$). The longest line is $3\to2$:
$$\frac1\lambda=4R\left(\frac14-\frac19\right)=\frac{5R}9,\qquad\lambda=\frac{9x}5.$$

(A)