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JEE Main 2026 · 5 Apr · Shift 2, Physics question 46

A copper wire of length 3 m is stretched by 3 mm by applying an external force. The volume of the wire is 600×10−6600\times10^{-6} m³. The elastic potential energy stored in the wire in stretched condition would be ________ J.

(Given Young modulus of copper =1.1×1011=1.1\times10^{11} N/m²)

Answer and worked solution

Official answer: 33

Energy stored.
U=12Y(ΔLL)2V=12(1.1×1011)(10−3)2(600×10−6)=33 J.U=\frac12Y\left(\frac{\Delta L}L\right)^2V=\frac12(1.1\times10^{11})(10^{-3})^2(600\times10^{-6})=33\text{ J}.

Answer: 33

Topics:Elastic potential energy
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