JEE Main 2026 · 5 Apr · Shift 2 · Physics Q41

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PhysicsSingle correct+4 / -1Question 41 of 75

An object $AB$ is placed 15 cm on the left of a convex lens $P$ of focal length 10 cm. Another convex lens $Q$ is now placed 15 cm right of lens $P$ . If the focal length of lens $Q$ is 15 cm, the final image is ________.

virtual, formed at 7.5 cm right of lens

Q

, with a size bigger than that of

AB

real, formed at 7.5 cm right of lens

Q

, with a size same as that of

AB

formed at infinity.

real, formed at 7 cm right of lens

Q

, with a size smaller than that of

AB

Answer and worked solution

Official answer: B

Lens P. $u=-15$ , $f=10$ , so $v=+30$ cm and $m_1=-2$ .

Lens Q (15 cm on). The image from P lies 15 cm beyond Q, so it is a virtual object at $u=+15$ :
$\frac1v=\frac1{15}+\frac1{15}\ \Rightarrow\ v=7.5\text{ cm},\qquad m_2=\frac{7.5}{15}=\frac12.$

Final image. $m=m_1m_2=-1$ : real, 7.5 cm right of Q, the same size as AB.

(B)

Topics:Combination of lenses and mirrors Thin lenses and lens maker's formula

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JEE Main 2026 · 5 Apr · Shift 2, Physics question 41