JEE Main 2026 · 5 Apr · Shift 2, Physics question 37

Steady state. No current flows in the capacitor branch. The 2 V cell drives current around the loop formed by its own branch (6 Ω) and the 2 Ω branch:
$$I=\frac2{6+2}=0.25\text{ A}.$$

Capacitor voltage. The capacitor branch (with its 4 Ω, carrying no current) is connected across the same two wires as the 2 Ω resistor:
$$V_C=0.25\times2=0.5\text{ V}.$$

(A)