JEE Main 2026 · 5 Apr · Shift 2 · Physics Q29

← JEE Main 2026 · 5 Apr · Shift 2

PhysicsSingle correct+4 / -1Question 29 of 75

The velocity ( $v$ ) versus time ( $t$ ) plot of a particle is shown in the figure, for a time interval of 40 s. The total distance travelled by the particle and the average velocity during this period are, respectively ________.

v (m/s) against t (s): v rises linearly from 0 to +5 at t = 10 s, falls to 0 at t = 20 s, falls to −5 at t = 30 s and returns to 0 at t = 40 s.

25 m and zero

50 m and zero

100 m and zero

100 m and 2.5 m/s

Answer and worked solution

Official answer: C

Distance. The graph is four triangles, each of area $\tfrac12\times10\times5=25$ m, so the distance is 100 m.

Displacement. The area above the axis cancels the area below it, so the displacement, and the average velocity, is zero.

(C)

Topics:Motion graphs

← Previous question Next question →

JEE Main 2026 · 5 Apr · Shift 2, Physics question 29