JEE Main 2026 · 5 Apr · Shift 2 · Mathematics Q20

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MathematicsSingle correct+4 / -1Question 20 of 75

Let $f(x)$ and $g(x)$ be twice differentiable functions satisfying $f''(x)=g''(x)$ for all $x\in\mathbf R$ , $f'(1)=2g'(1)=4$ and $g(2)=3f(2)=9$ . Then $f(25)-g(25)$ is equal to :

−20

−40

Answer and worked solution

Official answer: B

Difference. $f''=g''$ , so $f-g=Ax+B$ .

Constants.

$f'(1)=4$ and $g'(1)=2$ give $A=2$ .
$f(2)=3$ and $g(2)=9$ give $4+B=-6$ , so $B=-10$ .

Value: $f(25)-g(25)=50-10=40$ .

(B)

Topics:Higher-order derivatives

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JEE Main 2026 · 5 Apr · Shift 2, Mathematics question 20