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← JEE Main 2026 · 5 Apr · Shift 2
ChemistryInteger+4 / -1Question 75 of 75

JEE Main 2026 · 5 Apr · Shift 2, Chemistry question 75

For a reaction A→P\ce{A -> P} at T K, the half life (t1/2t_{1/2}) is plotted as a function of initial concentration [A]o[\mathrm A]_o of A as given below.

The value of xx in the given figure is ________ s (Nearest integer)

t½ (s) against [A]₀ (mol L⁻¹): a straight line through the origin; at [A]₀ = 1.5 × 10⁻³ it reads x, and at 4 × 10⁻³ it reads 240.
Answer and worked solution

Official answer: 90

Order. t1/2t_{1/2} is proportional to [A]o[\mathrm A]_o (a straight line through the origin). That is zero order: t1/2=[A]o2kt_{1/2}=\dfrac{[\mathrm A]_o}{2k}.

Read off x.
x=240×1.5×10−34×10−3=90 s.x=240\times\frac{1.5\times10^{-3}}{4\times10^{-3}}=90\text{ s}.

Answer: 90