JEE Main 2026 · 5 Apr · Shift 2 · Chemistry Q60

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ChemistrySingle correct+4 / -1Question 60 of 75

Given below are two statements :

Statement I: Presence of large number of unpaired electrons in transition metal atoms results in higher enthalpies of their atomisation.

Statement II: $d_{xy}=d_{xz}=d_{yz}<d_{x^2-y^2}=d_{z^2}$ and $d_{x^2-y^2}=d_{z^2}<d_{xy}=d_{xz}=d_{yz}$ are the d-orbital splittings in $\ce{[Fe(H2O)6]^3+}$ and $\ce{[NiCl4]^2-}$ complex ions respectively.

In the light of the above statements, choose the correct answer from the options given below :

Both Statement I and Statement II are correct

Both Statement I and Statement II are incorrect

Statement I is correct but Statement II is incorrect

Statement I is incorrect but Statement II is correct

Answer and worked solution

Official answer: A

Statement I. More unpaired d electrons give stronger metallic bonding, and so higher enthalpies of atomisation. Correct.

Statement II. Each splitting:

$\ce{[Fe(H2O)6]^3+}$ is octahedral: $t_{2g}\,(d_{xy},d_{xz},d_{yz})$ lies below $e_g\,(d_{x^2-y^2},d_{z^2})$ .
$\ce{[NiCl4]^2-}$ is tetrahedral: the order is reversed, e below $t_2$ .

Correct.

(A)

Topics:Crystal field theory Transition element properties

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JEE Main 2026 · 5 Apr · Shift 2, Chemistry question 60