JEE Main 2026 · 5 Apr · Shift 2, Chemistry question 57

One half cell in a voltaic cell is constructed by dipping silver rod in $\ce{AgNO3}$ solution of unknown concentration, other half cell is Zn rod dipped in 1 molar solution of $\ce{ZnSO4}$.

A voltage of 1.60 V is measured at 298 K for this cell. What is the concentration of $\ce{Ag+}$ ions used in terms of $\log x$ ($x=[\ce{Ag+}]$) ?

$E^\circ_{\ce{Zn^{2+}}/\ce{Zn}}=-0.76$ V, $E^\circ_{\ce{Ag+}/\ce{Ag}}=+0.80$ V, $\dfrac{2.303RT}F=0.059$ V