Skip to content
dronacharya.ai
← JEE Main 2026 · 5 Apr · Shift 2
ChemistrySingle correct+4 / -1Question 54 of 75

JEE Main 2026 · 5 Apr · Shift 2, Chemistry question 54

Consider the following data for the reaction

XX2(g)+YX2(g)⇌2 XY(g)\ce{X2(g) + Y2(g) <=> 2XY(g)}

at 600 K. The ΔrG∘\Delta_rG^\circ (in kJ mol−1^{-1}) for the reaction is :

Compound ΔfH600 K∘\Delta_fH^\circ_{600\,\mathrm K} (kJ mol−1^{-1}) S600 K∘S^\circ_{600\,\mathrm K} (J mol−1^{-1} K−1^{-1})
XY(g) 42 200
X₂(g) 8 140
Y₂(g) 80 250
Choose one option
Answer and worked solution

Official answer: B

Enthalpy. ΔrH∘=2(42)−(8+80)=−4\Delta_rH^\circ=2(42)-(8+80)=-4 kJ mol−1^{-1}.

Entropy. ΔrS∘=2(200)−(140+250)=10\Delta_rS^\circ=2(200)-(140+250)=10 J mol−1^{-1} K−1^{-1}.

Free energy.
ΔrG∘=−4−600(0.010)=−10 kJ mol−1.\Delta_rG^\circ=-4-600(0.010)=-10\text{ kJ mol}^{-1}.

(B)

Topics:Gibbs energy and spontaneityHess's law and enthalpies of reaction
← Previous questionNext question →