JEE Main 2026 · 5 Apr · Shift 1 · Physics Q49

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PhysicsInteger+4 / -1Question 49 of 75

The charged particle moving in a uniform magnetic field of $\left(3\hat i+2\hat j\right)$ T has an acceleration $\left(4\hat i-\dfrac x2\hat j\right)$ m/s². The value of $x$ is

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Answer and worked solution

Official answer: 12

Perpendicular. The magnetic force is perpendicular to $\vec B$ , so $\vec a\cdot\vec B=0$ :
$4(3)-\frac x2(2)=0\ \Rightarrow\ x=12.$

Answer: 12

Topics:Force on a moving charge

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JEE Main 2026 · 5 Apr · Shift 1, Physics question 49