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← JEE Main 2026 · 5 Apr · Shift 1
PhysicsInteger+4 / -1Question 47 of 75

JEE Main 2026 · 5 Apr · Shift 1, Physics question 47

From 18 m height above the ground a ball is dropped from rest. The height above the ground at which the magnitude of velocity equal to the magnitude of acceleration (in the same set of units) due to gravity is ________ m.
(Take g=10g=10 m/s² and neglect the air resistance)

Answer and worked solution

Official answer: 13

When v = 10 m/s. The ball has fallen v22g=10020=5\dfrac{v^2}{2g}=\dfrac{100}{20}=5 m.

Height above the ground: 18−5=1318-5=13 m.

Answer: 13