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← JEE Main 2026 · 5 Apr · Shift 1
PhysicsSingle correct+4 / -1Question 39 of 75

JEE Main 2026 · 5 Apr · Shift 1, Physics question 39

In Young's double slit experiment, the fringe width of the interference pattern produced on the screen is 2.4 μm. If the experiment is carried out in another medium having refractive index 1.2, the fringe width will be ________ μm.

Choose one option
Answer and worked solution

Official answer: B

Fringe width β=λDd\beta=\dfrac{\lambda D}d. In the medium, the wavelength becomes λ/μ\lambda/\mu:
β′=2.41.2=2 μm.\beta'=\frac{2.4}{1.2}=2\ \mu\text{m}.

(B)