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JEE Main 2026 · 5 Apr · Shift 1, Physics question 32

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R

Statement I: Change in internal energy of a system containing nn mole of ideal gas can be written as ΔU=nCv(Tf−Ti)=nRγ−1(Tf−Ti)\Delta U=nC_v\left(T_f-T_i\right)=\dfrac{nR}{\gamma-1}\left(T_f-T_i\right), where γ=CpCv\gamma=\dfrac{C_p}{C_v}, TiT_i = initial temperature, TfT_f = final temperature.

Statement II: Relation between degree of freedom ff and γ (=Cp/Cv)\gamma\ (=C_p/C_v) is (γ=1+2f)\left(\gamma=1+\dfrac2f\right)

Choose the correct answer from the options given below

Choose one option
Answer and worked solution

Official answer: B

Statement I (A). ΔU=nCvΔT\Delta U=nC_v\Delta T holds for an ideal gas in any process, and Cv=Rγ−1C_v=\dfrac R{\gamma-1}. True.

Statement II (R). Cv=f2RC_v=\tfrac f2R and Cp=(f2+1)RC_p=\left(\tfrac f2+1\right)R, so γ=1+2f\gamma=1+\tfrac2f. True.

Explanation? R relates γ to the degrees of freedom; it does not explain why ΔU=nRγ−1ΔT\Delta U=\tfrac{nR}{\gamma-1}\Delta T. So R is not the explanation of A.

(B)