JEE Main 2026 · 5 Apr · Shift 1 · Physics Q26

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In a Vernier calipers, when both jaws touch each other, zero of the Vernier scale is shifted to the right of zero of the main scale and 7th Vernier division coincides with a main scale reading. If the value of 1 main scale division is 1 mm and there are 10 Vernier scale divisions, then the Vernier caliper has

0.07 cm negative zero error

0.7 cm negative zero error

0.07 cm positive zero error

0.7 cm positive zero error

Answer and worked solution

Official answer: C

Least count. 10 VSD = 9 MSD, so LC $=1-0.9=0.1$ mm.

Zero error. The Vernier zero lies to the right of the main-scale zero, so the error is positive:
$7\times0.1\text{ mm}=0.7\text{ mm}=0.07\text{ cm}.$

(C)

Topics:Vernier callipers and screw gauge Least count

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JEE Main 2026 · 5 Apr · Shift 1, Physics question 26