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← JEE Main 2026 · 5 Apr · Shift 1
ChemistryInteger+4 / -1Question 75 of 75

JEE Main 2026 · 5 Apr · Shift 1, Chemistry question 75

If the half life of a first order reaction is 6.93 minutes then the time required for completion of 99% of the reaction will be ________ minutes .

(Given : log⁡2=0.3010\log 2 = 0.3010)

Answer and worked solution

Official answer: 46

Rate constant. k=0.6936.93=0.1k=\dfrac{0.693}{6.93}=0.1 min−1^{-1}.

99% completion.
t=2.303klog⁡1001=2.303×20.1=46.06 min.t=\frac{2.303}k\log\frac{100}1=\frac{2.303\times2}{0.1}=46.06\text{ min}.

Answer: 46