JEE Main 2026 · 5 Apr · Shift 1 · Chemistry Q72

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ChemistryInteger+4 / -1Question 72 of 75

In an estimation of sulphur by Carius method 0.2 g of the substance gave 0.6 g of $\ce{BaSO4}$ . The percentage of sulphur in the substance is ________%.

(Given molar mass in g mol $^{-1}$ S : 32, $\ce{BaSO4}$ : 231)

Your answer

Answer and worked solution

Official answer: 41

Carius method.
$\%\text{S}=\frac{32}{231}\times\frac{0.6}{0.2}\times100=41.56\%.$

Answer: 41 or 42 (both accepted by the key). With the true molar mass of $\ce{BaSO4}$ , 233, the value is 41.2.

Topics:Qualitative and quantitative analysis of organic compounds

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JEE Main 2026 · 5 Apr · Shift 1, Chemistry question 72