JEE Main 2026 · 5 Apr · Shift 1 · Chemistry Q58

ChemistrySingle correct+4 / -1Question 58 of 75

Given below are two statements:

Statement I: The correct order of electronegativity of fluorine, oxygen and nitrogen is F > O > N.

Statement II: The oxidation state of oxygen in $\ce{OF2}$ is +2 and in $\ce{Na2O}$ is −2.

In the light of the above statements, choose the correct answer from the options given below

Both Statement I and Statement II are true

Both Statement I and Statement II are false

Statement I is true but Statement II is false

Statement I is false but Statement II is true

Answer and worked solution

Official answer: A

Statement I. Electronegativities are F (4.0) > O (3.5) > N (3.0). True.

Statement II. F is always −1, so O is +2 in $\ce{OF2}$ . In $\ce{Na2O}$ , O is −2. True.

(A)

Topics:Electronegativity Oxidation number

JEE Main 2026 · 5 Apr · Shift 1, Chemistry question 58