JEE Main 2026 · 4 Apr · Shift 2 · Physics Q30

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The height in terms of radius of the earth ( $R$ ), at which the acceleration due to gravity becomes $\dfrac g9$ , where $g$ is acceleration due to gravity on earth's surface, is ________.

\sqrt3R

2\sqrt2R

2R

\dfrac49R

Answer and worked solution

Official answer: C

Variation with height. $g'=\dfrac g{(1+h/R)^2}=\dfrac g9$ , so $1+\frac hR=3$ and $h=2R$ .

(C)

Topics:Variation of g

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JEE Main 2026 · 4 Apr · Shift 2, Physics question 30