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← JEE Main 2026 · 4 Apr · Shift 2
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JEE Main 2026 · 4 Apr · Shift 2, Physics question 28

At t=0t=0, a body of mass 100 g starts moving under the influence of a force (5i^+10j^)\left(5\hat i+10\hat j\right) N. After 2 s its position is (2xi^+5yj^)\left(2x\hat i+5y\hat j\right) m. The ratio x:yx:y is ________.

Choose one option
Answer and worked solution

Official answer: D

Acceleration. a⃗=F⃗m=(50,100)\vec a=\frac{\vec F}m=(50,100) m/s².

From rest at the origin. r⃗=12a⃗t2=(100,200)\vec r=\frac12\vec at^2=(100,200) m.

Solve. 2x=1002x=100 and 5y=2005y=200, so x=50x=50, y=40y=40 and x:y=5:4x:y=5:4.

(D)