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← JEE Main 2026 · 4 Apr · Shift 2
MathematicsInteger+4 / -1Question 21 of 75

JEE Main 2026 · 4 Apr · Shift 2, Mathematics question 21

From a month of 31 days, 3 different dates are selected at random. If the probability that these dates are in an increasing A.P. is equal to ab\dfrac ab, where a,b∈Na,b\in\mathbb N and gcd⁡(a,b)=1\gcd(a,b)=1, then a+ba+b is equal to ________.

Answer and worked solution

Official answer: 944

Favourable choices. An increasing A.P. of dates is fixed by its first term and common difference d≥1d\ge1: ∑d=115(31−2d)=225\displaystyle\sum_{d=1}^{15}(31-2d)=225 choices.

Total. (313)=4495\binom{31}3=4495.

Probability 2254495=45899\frac{225}{4495}=\frac{45}{899}, so a+b=944a+b=944.

Answer: 944