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← JEE Main 2026 · 4 Apr · Shift 2
MathematicsSingle correct+4 / -1Question 17 of 75

JEE Main 2026 · 4 Apr · Shift 2, Mathematics question 17

Let A={(a,b,c):a,b,cA=\{(a,b,c):a,b,c are non-negative integers and a+b+2c=22}a+b+2c=22\}. Then n(A)n(A) is equal to:

Choose one option
Answer and worked solution

Official answer: C

Fix c (0≤c≤110\le c\le11). Then a+b=22−2ca+b=22-2c has 23−2c23-2c solutions.

Total. ∑c=011(23−2c)=276−132=144\displaystyle\sum_{c=0}^{11}(23-2c)=276-132=144.

(C)