JEE Main 2026 · 4 Apr · Shift 2 · Mathematics Q2

MathematicsSingle correct+4 / -1Question 2 of 75

Let $S=\{z\in\mathbb C:z^2+4z+16=0\}$ . Then $\displaystyle\sum_{z\in S}\left|z+\sqrt3i\right|^2$ is equal to:

Answer and worked solution

Official answer: D

Roots. $z=-2\pm2\sqrt3\,i$ .

Add $\sqrt3\,i$ . This gives $-2+3\sqrt3\,i$ and $-2-\sqrt3\,i$ , with squared moduli $4+27=31$ and $4+3=7$ .

Sum 38.

(D)

Topics:Modulus and argument Roots and coefficients

JEE Main 2026 · 4 Apr · Shift 2, Mathematics question 2