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← JEE Main 2026 · 4 Apr · Shift 2
ChemistryInteger+4 / -1Question 74 of 75

JEE Main 2026 · 4 Apr · Shift 2, Chemistry question 74

For a first order reaction A→B\ce{A -> B}

t/min [A]/M
0 0.6500
xx 0.0650
20 0.00065

xx = ________ min. (Nearest integer)

Answer and worked solution

Official answer: 7

First order. From 0.65 to 0.00065 M is a factor 10310^3 in 20 min, so each tenfold fall takes 203\frac{20}3 min.

x. 0.65 → 0.065 is one tenfold fall: x=6.67≈7x=6.67\approx7 min.

Answer: 7