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← JEE Main 2026 · 4 Apr · Shift 2
ChemistrySingle correct+4 / -1Question 69 of 75

JEE Main 2026 · 4 Apr · Shift 2, Chemistry question 69

Among FeX3+\ce{Fe^{3+}}, PbX2+\ce{Pb^{2+}}, CuX2+\ce{Cu^{2+}} and MnX2+\ce{Mn^{2+}}, identify the one that gets precipitated out while passing HX2S\ce{H2S} in presence of NHX4OH\ce{NH4OH} as group reagent. The highest possible oxidation state of the corresponding metal is

Choose one option
Answer and worked solution

Official answer: D

Group IV. HX2S\ce{H2S} with NHX4OH\ce{NH4OH} precipitates the group IV sulphides; of the ions listed this is MnX2+\ce{Mn^{2+}} (as MnS). (FeX3+\ce{Fe^{3+}} comes down earlier with the group III reagent NHX4OH\ce{NH4OH} alone; PbX2+\ce{Pb^{2+}} and CuX2+\ce{Cu^{2+}} belong to group II.)

Highest oxidation state of Mn is +7 (as in KMnOX4\ce{KMnO4}).

(D)