JEE Main 2026 · 4 Apr · Shift 2 · Chemistry Q58

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ChemistrySingle correct+4 / -1Question 58 of 75

The electronegativity of a group 13 element 'E' is same as that of Ge (on Pauling scale and upto one decimal point). The CORRECT statements about $\ce{E^{3+}}$ are

A. It can act as a reducing agent.

B. It can act as an oxidizing agent.

C. $\ce{E^{3+}}$ is more stable than $\ce{E+}$ .

D. The standard electrode potential value for $\ce{E^{3+}}$ /E is positive.

Choose the correct answer from the options given below:

A and C Only

B and C Only

B and D Only

A and D Only

Answer and worked solution

Official answer: C

Identify E. Ge has Pauling electronegativity ≈ 2.0. In group 13 the matching element is thallium (≈ 2.0 for Tl(III)).

Statements.

Inert-pair effect: $\ce{Tl+}$ is more stable than $\ce{Tl^{3+}}$ (C false).
So $\ce{Tl^{3+}}$ is an oxidising agent (B true), not a reducing agent (A false).
$E^\circ(\ce{Tl^{3+}}/\ce{Tl})\approx+0.72$ V is positive (D true).

B and D.

(C)

Topics:Group 13 Electronegativity

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JEE Main 2026 · 4 Apr · Shift 2, Chemistry question 58